31 lines
1.7 KiB
Java
31 lines
1.7 KiB
Java
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//This code is written by Siwat Sirichai
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import java.io.File;
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import java.io.FileNotFoundException;
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import java.util.Scanner;
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public class CountNumbers {
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public static void main(String[] args) {
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try { //Since java.io.File throws FileNotFoundException, a try-catch block is neccessary.
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Scanner sc = new Scanner(new File("numbers.txt")); //This create a scanner with file "number.txt" as an input
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int length = 0; //define array length initialy at zero
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for(length = 0;sc.hasNextInt();length++)sc.nextInt(); //Use File Scanner to find the number of elements in the file
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int[] int_array = new int[length]; //Create an array with length number of elements
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sc = new Scanner(new File("numbers.txt")); //Send the Scanner's cursor to the top of the file
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for(int i = 0;i<int_array.length;i++)int_array[i]=sc.nextInt(); //populate the array with the file's value
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System.out.println("The number of integers greater than 25: "+greater(int_array,25));
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System.out.println("The number of integers greater than 25: "+greater(int_array,50));
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System.out.println("The number of integers greater than 25: "+greater(int_array,75));
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} catch(FileNotFoundException e) {
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System.out.println("File \"numbers.txt\" is not found in the current directory!"); //If no fie named numbers.txt is found, show "File "numbers.txt" is not found in the current directory!" and exit the program with exit code 0
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System.exit(0);
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}
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}
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public static int greater(int[] a,int v) {
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int count = 0; //Create an int name count to store the number of numbers that are greater than a at all indexes
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for(int val : a)if(val>v)count++;//This is called a for-each loop, it will loop for a.length iteration,
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return count;
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}
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}
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